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2) A ball is hit at an angle of 36 degrees to the horizontal from 14 feet above the ground. If it hits the ground 26 feet away (in horizontal distance), what was the initial velocity? Assume there is no air resistance.

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  1. X = hor. = 26Ft.

    r(hyp.) = X / cosA = 26 / cos36=32.1Ft.

    Y = ver. = 32.1sin36 = 18.9Ft.

    d(down) = Vo + 0.5gt^2 = 18.9,
    0 + 4.9t^2 = 18.9.
    t^2 = 3.86,
    t = 1.96s.

    Vf^2 = Vo^2 + 2gd = 0,
    Vo^2 + 2*(-9.8)18.9 = 0,
    Vo^2 - 370.44 = 0,
    Vo^2 = 370.44,
    Vo(ver.) = 19.2m/s.

    Vo = 19.2 / sin36 = 32.7m/s.

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