Ask questions and get helpful answers.

I have a question which asks...

What is the Oxidation number of Nitrogen in Cu(NO3)2
I know the answer is 5+ but how do you get that??

Cu= 2+
O= 2- (Theres 3 of them so -2x3=-6...then, theres a two out of the brackets so 6- x 2 =-12)
+2 - (-12)= -10? And then what?
I think my method is wrong. :/ It's really frustrating and i've been at the same question for over an hour now.

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

2 answers

  1. See your post above.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. Cu=2+
    O=2-
    Put x for N
    Then ,
    2(ie cu)+2×((x+3×-2))=0 (3 times O is there so 3×-2 , also both N and and O are there two times..so multiply them with two)
    2+2x-12=0
    2x=10
    X=+5
    Hope you understood🙂

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.