A solution is prepared by dissolving 130 g of NaNO3 in 100 g of water at 80°C. The solution is cooled to 0°C. How many grams of compound remain in solution?
How many grams of solid are formed?
This is pretty easy. WAht is the saturated level (mass NaOH3 per 100gwater). Look at the solubility curves to get that.
http://www.goldrecovery.us/images/solgraph.jpg
Then, that point tells you how much is still in solution.
The difference is how much precipated.
do i find out what the saturated level is for 80C or 0C
The molarity of urea in a solution prepared by dissolving 16 g of urea (MW = 60.0 g/mol) in 39g of H2O is M. The density of the .solution is 1.3 g/mL 0.11 .a O 6.3 .b O 3.7 .C O 6.8 .d o 0.16 .e O
To find out how many grams of compound remain in solution when the solution is cooled to 0°C, we need to consider the solubility of NaNO3 in water at different temperatures.
First, we need to determine if NaNO3 is soluble in water at 0°C. We can do this by referring to the solubility chart or solubility product constant (Ksp) values. If the Ksp value is greater than the concentration of the compound at 0°C, then the compound is soluble; otherwise, it is insoluble.
Assuming NaNO3 is soluble in water at 0°C, we can use the solubility data to calculate the concentration (in grams) of NaNO3 in 100 g of water at 80°C and then determine how much of it remains in solution at 0°C.
1. Calculate the concentration of NaNO3 in the original solution:
The concentration (C) can be calculated using the formula:
C = mass of solute / mass of solvent
C = 130 g NaNO3 / (130 g NaNO3 + 100 g H2O)
C = 130 g / 230 g
C ≈ 0.565 g/g
2. Determine the solubility of NaNO3 at 0°C:
Assuming NaNO3 is soluble at 0°C, let's say the solubility is x g/g.
3. Calculate the amount of NaNO3 remaining in solution at 0°C:
Since the amount of water remains constant during cooling, the remaining NaNO3 can be calculated using the formula:
mass of NaNO3 remaining = concentration at 0°C * mass of water at 0°C
mass of NaNO3 remaining = x g/g * (100 g H2O)
The amount of solid that forms when the solution is cooled also depends on the amount of compound that is unable to remain in solution at 0°C. Therefore, the grams of solid formed will be equal to the mass of NaNO3 that precipitates out of the solution.
Finally, we can calculate the grams of solid formed by using the difference between the original amount of NaNO3 (130 g) and the remaining amount of NaNO3 at 0°C.
grams of solid formed = 130 g - (x g/g * (100 g H2O))
Please note that the solubility value (x) for NaNO3 at 0°C needs to be obtained from a reliable source, such as experimental data or a solubility chart, to get an accurate answer.