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the velocity of the water jet discharging from the orifice can be obtained from v = (2gh)^(1/2), where h = 2m is the depth of the orifice from the free water surface. determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits the surface.

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  1. Vx = sqrt(2gh)
    y=y0 + Vy *t - 1/2gt^2
    -1.5= -1/2gt^2
    solve for t
    t= 0.553
    x=x0 + vx*t ,x0 = 0
    x=3.4641m

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  2. That will depend upon how far below the orifice that point B is. A figure should tell you that. We cannot see your figure.

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