If 111.70 g of iron react with oxygen gas to produce iron (III) oxide, how many moles of oxygen gas will be needed?
Here is a worked example.
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To determine the number of moles of oxygen gas needed, we need to use the molar ratio between iron and oxygen in the balanced chemical equation.
The balanced chemical equation for the reaction between iron and oxygen gas to produce iron (III) oxide is:
4Fe + 3O2 -> 2Fe2O3
From the balanced equation, we can see that 4 moles of iron react with 3 moles of oxygen gas to produce 2 moles of iron (III) oxide.
To find the number of moles of oxygen gas, we can use the following proportion:
(3 moles of oxygen gas) / (4 moles of iron) = (x moles of oxygen gas) / (111.70 g of iron)
Cross-multiplying, we have:
3 moles of oxygen gas * (111.70 g of iron) = 4 moles of iron * (x moles of oxygen gas)
333.1 g of oxygen gas = 4x moles of oxygen gas
Dividing both sides by 4, we get:
x moles of oxygen gas = 333.1 g of oxygen gas / 4
Therefore, approximately 83.28 moles of oxygen gas will be needed.
To determine the number of moles of oxygen gas needed, we need to use the balanced chemical equation for the reaction between iron and oxygen gas to form iron (III) oxide.
The balanced equation is:
4 Fe + 3 O2 -> 2 Fe2O3
From the coefficient ratio in the balanced equation, we can determine the molar ratio between iron and oxygen gas.
The molar ratio is: 4 moles of iron : 3 moles of oxygen gas
Now, let's calculate the number of moles of oxygen gas required using the given mass of iron (111.70 g) and the molar mass of iron (Fe) and oxygen (O2).
The molar mass of iron is 55.845 g/mol, and the molar mass of oxygen gas (O2) is 32.00 g/mol.
First, we need to convert the mass of iron to moles. We can use the formula:
moles of iron = mass of iron / molar mass of iron
moles of iron = 111.70 g / 55.845 g/mol = 1.998 mol (rounded to three decimal places)
Since the molar ratio between iron and oxygen gas is 4:3, the number of moles of oxygen gas will be:
moles of oxygen gas = (moles of iron) x (3 moles of oxygen gas / 4 moles of iron)
moles of oxygen gas = 1.998 mol x (3/4) = 1.4985 mol (rounded to four decimal places)
Therefore, 1.4985 moles of oxygen gas will be needed to react with 111.70 g of iron to produce iron (III) oxide.
determine the normality of 38g of HCI in 6.2 L of solution.
my answer 0.17
is that correct?