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if ED=10 and DB=3x-8 whats the lenght of EB

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  1. There are in fact three cases.

    Case 1: (seemingly obvious case)
    E-----D--------B
    ED=10
    DB=3x-8
    EB=10+3x-8=3x+2

    Case 2:
    E-----B-------D
    ED=10
    DB=3x-8
    EB=10-(3x-8)=18-3x=3(6-x)

    Case 3:
    D-----E--------B
    ED=10
    DB=3x-8
    EB=3x-8 - 10 = 3x-18=3(x-6)

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