Ask questions and get helpful answers.

Calculate the percent ionization of a 0.15 formic acid solution in a solution containing 0.11 potassium formate.

I have the formic acid Ka=1.8 *10^-4
When I solve for "x" I'm getting 1.1.44*10^-2 When I plug that into equation (x/0.15-x)*100, I'm getting 10.6% which is incorrect. I getting lost in the math, plz help. Thanks

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

2 answers

  1. I don't believe it's the math. Let's simplify the formic acid and call it HF (I know that isn't right but it saves typing).
    HF ==> H^+ + F^- and KF ==>K^+ + F^-
    HF = 0.15M at the start. F^- from KF = 0.11
    (H^+)(F^-)/(HF) = Ka
    (H^+) = x
    (F^-) = x + 0.11 but since x is small we can make this equal to 0.11.
    (HF) = 0.15-x but since x is small we can make this equal 0.15.
    Solve for x = (H^+). I get an answer of 2.45E-4 = (H^+). By the way, I solved the quadratic we get if we keep x+0.11 and 0.15-x and I get 2.445E-4 so there is almost no error in making the assumptions.
    Then % ion = (ions/0.15)*100 = (2.45E-4/0.15)*100 =??
    Note that I've carried too many significant figures, you should correct that, especially if you are keying the answer into a database.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. Thank you so much! I see what I was doing wrong now. I need more practice with these type problems.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.