to what volume should you dilute 0.100 L of a 15M NaOH solution to obtain a 1.0 M NaOH solution?
MiVi = MfVf
See dilution example:
http://chemistry.about.com/od/lecturenotesl3/a/concentration.htm
1.5 L
To dilute a 15M NaOH solution to a 1.0 M NaOH solution, you can use the dilution formula, which is as follows:
C1V1 = C2V2
where:
C1 = initial concentration of the solution (in moles per liter)
V1 = initial volume of the solution (in liters)
C2 = final concentration of the solution (in moles per liter)
V2 = final volume of the solution (in liters)
In this case, we have:
C1 = 15M
V1 = 0.100 L
C2 = 1.0 M
V2 = ?
Plugging in these values into the dilution formula, we get:
15M × 0.100 L = 1.0 M × V2
Solving for V2, we have:
V2 = (15M × 0.100 L) / 1.0 M
V2 = 1.5 L
Therefore, you need to dilute the 0.100 L of 15M NaOH solution to a final volume of 1.5 L in order to obtain a 1.0 M NaOH solution.
To calculate the volume you should dilute, you can use the equation for dilution:
C1V1 = C2V2
where C1 and C2 are the initial and final concentrations respectively, and V1 and V2 are the initial and final volumes respectively.
Given:
C1 = 15 M (initial concentration)
V1 = 0.100 L (initial volume)
C2 = 1.0 M (final concentration)
Let's solve for V2:
C1V1 = C2V2
15 M * 0.100 L = 1.0 M * V2
Now, rearrange the equation to solve for V2:
V2 = (C1V1) / C2
Substituting the given values:
V2 = (15 M * 0.100 L) / 1.0 M
V2 = 1.5 L
Therefore, you should dilute the 0.100 L of a 15M NaOH solution to a final volume of 1.5 L to obtain a 1.0 M NaOH solution.