a 0.75 kg mass attached to avertical spring streches the spring 0.30m. what is the spring constant? the massspring system is now placed on the horizontal surface and set vibrating. what is the period of the vibration?
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2 answers

k = F/(deflection) = M*g/(0.30 m)
= ___ N/m
P = 2 pi sqrt(M/k) = ____ seconds
Changing from vertical to horizontal vibration does not change the period in a frictionless situation. There might however be more friction when vibrating horizontally, and this makes the period slightly larger. To make an estimate, you would need to know the friction coefficient. They probably expect you to neglect friction 👍
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drwls 
k= 24.525n/m
t= 1.098s 👍
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Anonymous
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