When sodium chloride reacts with silver nitrate, silver chloride precipitates. What mass of AgCl is produced from 192 g of AgNO3? Answer in units of g.
To determine the mass of silver chloride (AgCl) produced from 192 g of silver nitrate (AgNO3), we need to use the stoichiometry of the reaction.
The balanced chemical equation for the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3) is:
AgNO3 + NaCl → AgCl + NaNO3
From the balanced equation, we can see that one mole of AgNO3 reacts with one mole of NaCl to produce one mole of AgCl.
First, we need to convert the given mass of AgNO3 (192 g) to moles. We can do this by using the molar mass of AgNO3.
The molar mass of AgNO3 is calculated as follows:
AgNO3: (1 x Ag) + (1 x N) + (3 x O) = 107.87 g/mol + 14.01 g/mol + (3 x 16.00 g/mol) = 169.87 g/mol
To find the number of moles of AgNO3, we use the formula:
moles = mass / molar mass
moles of AgNO3 = 192 g / 169.87 g/mol = 1.13 mol
Since the stoichiometry of the balanced equation tells us that one mole of AgNO3 produce one mole of AgCl, we can conclude that 1.13 mol of AgNO3 will also produce 1.13 mol of AgCl.
Finally, we need to convert the moles of AgCl to grams using its molar mass.
The molar mass of AgCl is calculated as follows:
AgCl: (1 x Ag) + (1 x Cl) = 107.87 g/mol + 35.45 g/mol = 143.32 g/mol
To find the mass of AgCl, we use the formula:
mass = moles x molar mass
mass of AgCl = 1.13 mol x 143.32 g/mol ≈ 161.8 g
Therefore, the mass of AgCl produced from 192 g of AgNO3 is approximately 161.8 grams.
To find the mass of AgCl produced, we need to use stoichiometry, which involves calculating the moles of reactants and products.
First, we need to determine the balanced chemical equation for the reaction between sodium chloride (NaCl) and silver nitrate (AgNO3):
NaCl + AgNO3 -> AgCl + NaNO3
From the balanced equation, we can see that the stoichiometric ratio between AgNO3 and AgCl is 1:1. This means that for every 1 mole of AgNO3, we will form 1 mole of AgCl.
1 mole of any substance is numerically equal to its molar mass in grams. The molar mass of NaCl is 58.44 g/mol, and that of AgNO3 is 169.87 g/mol.
Let's calculate the number of moles of AgNO3 in 192 g using its molar mass:
Moles of AgNO3 = Mass of AgNO3 / Molar mass of AgNO3
= 192 g / 169.87 g/mol
≈ 1.13 mol
Since the stoichiometric ratio between AgNO3 and AgCl is 1:1, the number of moles of AgCl produced is also 1.13 mol.
Finally, we can calculate the mass of AgCl using its molar mass (143.32 g/mol):
Mass of AgCl = Moles of AgCl * Molar mass of AgCl
= 1.13 mol * 143.32 g/mol
≈ 162.16 g
Therefore, approximately 162.16 grams of AgCl is produced from 192 grams of AgNO3.
Follow the steps.
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