WHAT IS PRESSURE EXERTED OUTWARDLY IN A CYCLINDER THAT HAS ONE END CLOSED AND THE OTHER OPEN WHEN AN INTERNAL HEAT SOURCE RAISES THE TEMPERATURE FROM 70 DEGREE F TO 300 DEGREE F IF THE CYCLINDER IS 48 INCHES DIAMETER AND 240 INCHES LONG

Please use lower-case letters as it is much more difficult to read capital letters. Some of us will not bother.

Sra

To calculate the pressure exerted outwardly in a cylinder with one end closed and the other open when an internal heat source raises the temperature, you should use the ideal gas law. The ideal gas law relates the pressure, volume, temperature, and number of moles of gas in a system.

1. Determine the initial and final temperatures in Kelvin:
- Initial temperature (T1) = 70 °F + 459.67 (to convert to Rankine scale)
- Final temperature (T2) = 300 °F + 459.67

2. Convert the diameter (D) of the cylinder into radius (r):
- Radius (r) = diameter (D) / 2

3. Calculate the volume (V) of the cylinder:
- Volume (V) = π * r^2 * height (h)
(Use the converted radius and given height of 240 inches)

4. Convert the volume (V) from cubic inches to cubic feet:
- Volume (V) = V / 1728

5. Convert the pressure from pounds per square inch (psi) to pounds per square foot (psf):
- Pressure (P) = psi * 144

6. Rearrange the ideal gas law equation to solve for pressure (P):
- P1 = (P * V2 * T1) / (V1 * T2)
(P1 is the initial pressure, P is the unknown pressure)

7. Plug in the known values into the equation and solve for P:
- P = (P1 * V1 * T2) / (V2 * T1)
(P1 is the initial pressure, V1 is the initial volume, T1 is the initial temperature)
(V2 is the final volume, T2 is the final temperature)

By following these steps and plugging in the appropriate values, you can calculate the pressure exerted outwardly in the cylinder.