What is the concentration of a HNO3 solution if 10.0 mL of the solution is neutralized by 3.6 mL of a 0.20 M NaOH solution?
march 10
m1=m2v2/v1
m1=(0.20M NaCl)*(.0036)/(0.01)
m1=7.2x10^-4/(0.01)
m1=0.072
kkn
Well, if 10.0 mL of the HNO3 solution is neutralized by 3.6 mL of a 0.20 M NaOH solution, we can calculate the concentration of the HNO3 solution.
But before that, let me tell you a chemistry joke to lighten the mood:
Why did the chemist take a bath?
Because they wanted to Chemically Bond!
Now, back to your question. We need to use the equation:
M1V1 = M2V2
Where:
M1 = concentration of HNO3 solution
V1 = volume of HNO3 solution
M2 = concentration of NaOH solution
V2 = volume of NaOH solution
Given that V1 = 10.0 mL, V2 = 3.6 mL, and M2 = 0.20 M, we can rearrange the equation to solve for M1:
M1 = (M2 * V2) / V1
M1 = (0.20 M * 3.6 mL) / 10.0 mL
M1 = 0.072 M
So, the concentration of the HNO3 solution is 0.072 M. I hope this answer adds a little dose of laughter to your day!
To find the concentration of the HNO3 solution, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between HNO3 and NaOH.
First, let's write the balanced chemical equation for the reaction:
HNO3 + NaOH → NaNO3 + H2O
From the balanced equation, we can see that 1 mole of HNO3 reacts with 1 mole of NaOH to produce 1 mole of NaNO3 and 1 mole of H2O.
We are given that 10.0 mL of the HNO3 solution is neutralized by 3.6 mL of a 0.20 M NaOH solution.
To get the moles of NaOH used in the reaction, we can calculate:
moles of NaOH = volume of NaOH solution (in liters) × concentration of NaOH solution
= 3.6 mL × (1 L / 1000 mL) × 0.20 M
= 0.00072 moles
Since HNO3 and NaOH react in a 1:1 ratio, the moles of HNO3 used in the reaction are also 0.00072 moles.
The volume of the HNO3 solution is given as 10.0 mL.
To find the concentration of the HNO3 solution, we use the formula:
concentration (in moldm^-3) = moles of solute / volume of solution (in liters)
= 0.00072 moles / (10.0 mL × (1 L / 1000 mL))
= 0.072 M
Therefore, the concentration of the HNO3 solution is 0.072 M.
m1v1=m2v2
m1=m2v2/v1
m1=(0.20M NaCl)(.0036)/(0.01)
m1=7.2x10^-4(0.01)
m1=7.2x10^-6