use 6 of the digits from 1 to 9 to make each number. use each digit only once
the greatest possible number with 3 ten thousands
( I don't get this one at all)
The "3 ten thousands" part means that your number will be
_3_,_ _ _
Now fill in the rest of the numbers with the largest digits.
938,765
I DONT GET IT
The way I interpret your question:
You want a 6 digit number, no zeros, where the ten thousand position is a 3
eg. 436,127, or ?3?,???
if that is the case, the question is quite simple.
9x1x8x7x6x5
= 15120
= the total number of such numbers
the largest such number would of course be
938765
938765
938765
EASY 938765
To find the greatest possible number with 3 ten thousands using digits from 1 to 9, you need to determine the highest digit that can be placed in the ten-thousands place.
Since each digit can be used only once, the highest digit we can use is 9. Therefore, we will use 9 as the first digit in the ten-thousands place.
Next, we need to select the remaining digits for the remaining places. We have five digits left: 1, 2, 3, 4, and 5.
To maximize the value of the number, we want to place the highest remaining digits in descending order from left to right. So, the number will look like this: 9 _ _ _ _.
To determine the second-highest digit, we can compare the remaining digits 5, 4, 3, 2, and 1. Since 5 is the highest among them, we will place it in the thousands place. The number now looks like this: 9 5 _ _ _.
For the hundreds place, we select the next highest digit, which is 4. The number now looks like this: 9 5 4 _ _.
For the tens place, we select 3 since it is the next highest digit. The number now looks like this: 9 5 4 3 _.
For the ones place, we are left with digits 2 and 1. Since we want to maximize the value of the number, we place the highest remaining digit, which is 2, in the ones place. The final number is: 9 5 4 3 2.
Therefore, the greatest possible number with 3 ten thousands using digits from 1 to 9 is 95,432.