Graph the following equations; calculate the slope, x-intercept, and y-intercept, and label the intercepts on the graph.

Find the area of a rectangle if three of its corners are (-0.1,-3.4), (-7.9,-3.4), and (-0.1,6.8).

A(-7.9, -3.4), B(-0.1, -3.4).

b=hor. = -0.1-(-7.9) = 7.8 = The Base.

B(-0.1, -3.4), C(-0.1, 6.8),
h=ver.=6.8-(-3.4) = 10.2 = The height.

A = bh = 7.8 * 10.2 = 79.6

To graph the equations, we need to know the algebraic form of the equations. Could you please provide the equations you want to graph?

To find the area of a rectangle, we need the coordinates of all four corners. Since you provided three coordinates, we can calculate the fourth corner.

Here are the given coordinates:
Corner 1: (-0.1, -3.4)
Corner 2: (-7.9, -3.4)
Corner 3: (-0.1, 6.8)

To find the fourth corner, we can use the fact that opposite sides of a rectangle are equal in length. Since Corner 1 and Corner 2 have the same y-coordinate (-3.4), the fourth corner should have the same y-coordinate as Corner 3.

Using this information, we can calculate the coordinates of the fourth corner:
Corner 4: (-7.9, 6.8)

Now that we have all four corners, we can calculate the area of the rectangle using the formula: area = length Γ— width.

To calculate the length, we can find the distance between Corner 1 and Corner 3. The length is the difference between their x-coordinates:
Length = abs(-0.1 - (-7.9)) = abs(7.8) = 7.8

To calculate the width, we can find the distance between Corner 1 and Corner 2. The width is the difference between their y-coordinates:
Width = abs(-3.4 - 6.8) = abs(-10.2) = 10.2

Now we can calculate the area:
Area = Length Γ— Width = 7.8 Γ— 10.2 = 79.56

Therefore, the area of the rectangle is 79.56 square units.