a skateboarder is skating over a circular bump. she is at the top of the bump and is moving with a speed of 5m/s.

Is the normal force exerted on the skateboarder by the bump greater than, less than, or equal to the weight of the skateboarder?

explain. thanks.

the normal force exerted on the skateboarder is less than the weight

To determine whether the normal force exerted on the skateboarder by the bump is greater than, less than, or equal to the weight of the skateboarder, we need to consider the forces acting on the skateboarder at the top of the bump.

At the top of the bump, the skateboarder is experiencing two forces: the gravitational force (weight) acting downwards and the normal force exerted by the bump acting vertically upwards.

Since the skateboarder is moving along a curved path, there must be a net inward force acting towards the center of the curve. This force is called the centripetal force and is responsible for keeping the skateboarder moving in a circular path.

The normal force is the contact force exerted by a surface perpendicular to that surface. In this situation, the normal force acts perpendicular to the surface of the bump and opposes the gravitational force acting downwards.

To maintain the circular motion, the centripetal force must be provided by the net inward force, which is the difference between the normal force and the gravitational force.

If the normal force is greater than the weight of the skateboarder, then the net inward force will be greater than zero, and the skateboarder will continue moving in a circular path.

If the normal force is equal to the weight of the skateboarder, then the net inward force will be zero. In this case, the skateboarder will not experience any net force and will move in a straight line.

If the normal force is less than the weight of the skateboarder, then the net inward force will be less than zero, and the skateboarder will start to lose contact with the bump and move off the circular path.

Since the skateboarder is moving along a curved path and not losing contact with the bump, it suggests that the normal force exerted on the skateboarder by the bump is greater than the weight of the skateboarder.

Therefore, the normal force exerted on the skateboarder by the bump is greater than the weight of the skateboarder.

To determine whether the normal force exerted on the skateboarder by the bump is greater than, less than, or equal to the weight of the skateboarder, we need to consider the forces acting on the skateboarder at the top of the circular bump.

In this scenario, the skateboarder is moving with a constant speed at the top of the bump. Since she is not accelerating, the net force acting on her must be zero (according to Newton's first law). In other words, the sum of the forces in the vertical direction must balance out.

The forces acting on the skateboarder at the top of the bump are gravity (weight) and the normal force exerted by the bump. The weight of the skateboarder always acts vertically downward, regardless of her motion. This force is given by the equation: weight = mass x acceleration due to gravity.

Now, when the skateboarder is at the top of the bump, the normal force exerted by the bump is directed perpendicular to the surface of the bump. Its magnitude can be calculated using the centripetal force formula: Fc = m * v^2 / r, where Fc represents the centripetal force, m is the mass, v is the velocity, and r is the radius of the circular path.

Since the skateboarder is moving at a constant speed, the centripetal force is balanced by the normal force. Therefore, these forces must be equal in magnitude, as they cancel each other out in the vertical direction.

Hence, at the top of the bump, the normal force exerted on the skateboarder by the bump is equal to the weight of the skateboarder.