How much work must be done to stop a 1250 kg car traveling at 105 km/h?

First convert km/h to m/s because we need the answer to be J, which is Kg/m^2/s^2

105km/h=29.2 m/s (the rule is, to go from km/h to m/s is divide by 3.6)
W=1/2mv^2
W=(0.5)(1250)(29.2)^2
W=531684J
AND, because the work is being done to slow something down, it is negative.
So the answer is -531684J. (the comment above me is correct, I just wanted to provide an explanation for anyone who wanted to know how he/she above me got to the correct answer)

physics sucks

-531685J

To calculate the work required to stop a car, we need to use the work-energy principle. The work-energy principle states that the work done on an object is equal to the change in its kinetic energy.

First, we need to calculate the initial kinetic energy (KE) of the car using the formula:

KE = (1/2) * mass * velocity^2

where:
- KE is the initial kinetic energy,
- mass is the mass of the car (given as 1250 kg),
- velocity is the initial velocity of the car (105 km/h).

Converting the velocity from km/h to m/s, we get:

velocity = 105 km/h * (1000 m/1 km) * (1 h/3600 s) = 29.17 m/s (rounded to two decimal places)

Plugging the mass and velocity into the kinetic energy formula:

KE = (1/2) * 1250 kg * (29.17 m/s)^2 = 527,118.23 J (rounded to two decimal places)

Now, let's assume that the car needs to come to a complete stop. In this case, the final kinetic energy will be zero.

The work done to stop the car is the difference between the initial kinetic energy and the final kinetic energy, as work is equal to the change in kinetic energy:

Work = Final KE - Initial KE

Work = 0 J - 527,118.23 J

Work = -527,118.23 J (rounded to two decimal places)

The negative sign indicates that work is being done to oppose the car's motion.

Therefore, the work required to stop the car is approximately -527,118.23 J.

531684.027J

5.3x〖10〗^5 J

So then you have to convert it to joules?

131,250

you will first of all conevert km/h to m/s which is 105 multiply 1000 then divide by 3600= 29.7.

use the formula f= ma.
1250 multiply by 9.8=12250
then use formula for work
w=f multiply by distance
w=12250 multiply by 29.7=363825J.

Work is Force multiplied by distance.

1250*105=?
Your answer will be in watts.