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A box sits on a horizontal wooden board. The coefficient of static friction between the box and the board is 0.41. You grab one end of the board and lift it up, keeping the other end of the board on the ground. What is the angle between the board and the horizontal direction when the box begins to slide down the board?

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3 answers
  1. njnj

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  2. 22.29
    22deg

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  3. Mg = Force of box = Normal force,Fn.
    Fp = Mg*sin A. = Force parallel with incline.
    Fs = u*Fn = 0.41Fn = 0.41Mg = Force of static friction.
    Fp-Fs = M*a
    Mg*sin A-0.41Mg = M*0 = 0.
    Divide both sides by Mg:
    sin A-0.41 = 0
    A = 24.2 Degrees.

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