What is the probability of rolling at least one double-6 with 24 rolls of two fair dice?
Should that be 24 PAIRS of two fair dice?
no, you roll 2 die 24 times
The probability of not throwing a double six in 24 throws is:-
=power((35/36),24)) = 0.5087
The answer should be 1 - 0.5087 then, which equals 0.4913.
(I couldn't wrap my brain around this, so I googled "dice probability double 6" without quotes. The above statement came from a website called "Probability Theory.")
crazy
To calculate the probability of rolling at least one double-6 with 24 rolls of two fair dice, we can break it down into the probability of not rolling a double-6 in any single roll.
The probability of not rolling a double-6 on one roll is the complement of rolling a double-6, which is 1 minus the probability of rolling a double-6.
The probability of rolling a specific number on two dice (in this case, double-6) is 1/36 because there are 36 possible outcomes when rolling two dice, and only one of those outcomes is a double-6.
So, the probability of not rolling a double-6 on one roll is 1 - (1/36) = 35/36.
Since we want to find the probability of not rolling a double-6 in any of the 24 rolls, we multiply the individual probabilities together:
(35/36) * (35/36) * (35/36) * ... * (35/36) (24 times)
To calculate this expression, you can use a calculator or a computer program.
Finally, to find the probability of rolling at least one double-6, we subtract the probability of not rolling a double-6 from 1:
1 - ( (35/36) * (35/36) * ... * (35/36) ) (24 times)
This gives us the probability of rolling at least one double-6 with 24 rolls of two fair dice.