An electrical circuit switches instantaneously from a 2 volt battery to a 20 volt battery 3 seconds after being turned on. Sketch on a sheet of paper a graph the battery voltage against time. Then fill in the formulas below for the function represented by your graph.
For t < _____ , V(t) = _____
For t ¡Ý _____, V(t) = _____
At what point or points is your function discontinuous?
t = ______
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The change occurred at t=3 seconds.
So at t<3 seconds, V(t)=2 volts
at t>3 seconds, V(t)=? volts
Discontinuity is at t=?
t < 8 V(t) =5
T>8 V(t) =18
t=8
if two resistors with resistances r1 and r2 ohms are connected in parallel in an electric circuit to make an r-ohms resistor , the value of r can be found from the equation 1/r=1/r1+1/r2. if r1 is decreasing at the rate of 1 ohm/sec , and r2 is increasing at the rate of 0.5 ohm/sec , at what rate is r changing when r1=75 ohms and r2=50 ohms
An electrical circuit switches instantaneously from a 3 volt battery to a 23 volt battery 7 seconds after being turned on. Sketch on a sheet of paper a graph the battery voltage against time. Then fill in the formulas below for the function represented by your graph.
Oh boy, I'm no artist, but I'll do my best to sketch this for you. Let's call the time when the circuit turns on, t = 0.
For t < 3 seconds, V(t) = 2 volts (from the 2 volt battery).
For t ≥ 3 seconds, V(t) = 20 volts (after switching to the 20 volt battery).
So, now let's recap:
For t < 3, V(t) = 2.
For t ≥ 3, V(t) = 20.
Hmm, as for the discontinuity, it occurs at t = 3 seconds, where the battery voltage suddenly jumps from 2 volts to 20 volts. It's like the circuit got a shock of energy! Yikes!
I hope that helps! Let me know if you have any more shocking questions!
To sketch the graph of the battery voltage against time, let's consider the information given.
Initially, the circuit is connected to a 2 volt battery. Hence, for t < 3 seconds, the voltage remains constant at 2 volts.
Next, at t = 3 seconds, the circuit switches instantaneously to a 20 volt battery. From this point onward (t ≥ 3 seconds), the voltage remains constant at 20 volts.
Therefore, the graph can be sketched as follows:
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Now, let's fill in the formulas for the function represented by the graph:
For t < 3 seconds, V(t) = 2 volts.
For t ≥ 3 seconds, V(t) = 20 volts.
The function is discontinuous at t = 3 seconds because there is an abrupt change in voltage at this point.