Charlie is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices.

Company A charges $127 and allows unlimited mileage.
Company B has an initial fee of $55.00 and charges an additional $0.90 for every mile driven.
For what mileages will Company A charge at least as much as Company B? Use m for the number of miles driven, and solve your inequality for m .

a=127
b=55+.9m
127=55+.9m
72=.9m
m=80

Yes.

I think it has to be written as

m<= 80

if the answer should be m<=80 I don't have an equal answer option. Thanks

Then trust PsyDAG. He knows math!

To find the mileages at which Company A charges at least as much as Company B, we need to set up an inequality.

Let's assign variables to the prices for each company.
a represents the price for Company A, which is $127.
b represents the price for Company B, which consists of an initial fee of $55 and an additional charge of $0.90 for every mile driven. So, the equation for Company B's price is: b = 55 + 0.9m, where m is the number of miles driven.

We want to find the mileages (represented by m) at which Company A charges at least the same as Company B. In other words, we want to find the values of m for which a is greater than or equal to b.

So, we set up the inequality: a ≥ b
Substituting the values, we have:
127 ≥ 55 + 0.9m

Now, let's solve for m.

First, subtract 55 from both sides of the inequality:
127 - 55 ≥ 0.9m

Simplifying this, we get:
72 ≥ 0.9m

Next, divide both sides of the inequality by 0.9 to isolate m:
72 / 0.9 ≥ m

Doing the division, we find:
80 ≥ m

So, the inequality m ≤ 80 represents the mileages at which Company A charges at least as much as Company B. This means that if Charlie drives 80 miles or fewer, Company A will charge at least the same amount as Company B.