three identical blocks are pulled on a horizontal frictionless surface. if the tension in the rope held by the habd is 30N what is the tension in the other ropes?
they would vary in the ratio of the mass that is being pulled by the string.
Since the surface is frictionless, all the blocks would accelerate in a similar manner, that is, they have the same value of acceleration.
So if the string attached to block 3 is pulled by 30N,
acceleration= 30/(3m)=10/(m); where, 'm' is the mass of each block.
tension on string pulling block 2 = 2m*(10/m)=20N
tension on string pulling block 1= 1m*(10/m)= 10N
Well, isn't that a knot-so-simple question! Let's unravel the mystery together, shall we?
Since the blocks are identical and there is no friction, we can assume that the tension in each rope is the same. So if the tension in the rope held by the hand is 30N, then the tension in the other ropes is also 30N.
In other words, all the ropes are pulling their weight and tension is equally shared among them. Just like a team of clowns working in perfect harmony!
So, the tension in the other ropes is also 30N. It's a tight-knit group, after all!
To find the tension in the other ropes, we need to consider the equilibrium of forces acting on the blocks.
Since the blocks are identical and pulled on a horizontal frictionless surface, the tension in all three ropes must be equal in order to maintain equilibrium.
Therefore, the tension in each of the other two ropes would also be 30N.
To find the tension in the other ropes, we can start by understanding the forces acting on the blocks. Since the blocks are identical, they have the same mass, denoted by "m". The forces acting on each block are as follows:
1. The tension force (T) acting in the direction of motion.
2. The weight force (mg) acting vertically downwards.
Since the blocks are pulled horizontally, the vertical weight force does not affect the tension in the ropes. Therefore, the only force that contributes to the tension is the tension force.
Now, let's analyze the system. When the blocks are connected in a series, the total tension force is shared equally among the blocks. In this case, we have three blocks, so the total tension force is divided by three.
Given that the tension in the rope held by the hand is 30N, we can divide it equally among the three ropes:
Tension in each rope = Total tension force / Number of ropes
= 30 N / 3
= 10 N
Therefore, the tension in each of the other two ropes is 10 Newtons.