Pure gold has a density of 19 g/ml. If you bought a gold ring and found it had a volume of 0.3 ml and it weighed 5.7 grams, is it real gold? Show me your calculation

density x volume=weight

19.32x0.3=5.76

To determine whether the ring is made of real gold, we can calculate its density using the given volume and weight, and compare it to the density of pure gold.

1. Calculate the density of the ring:
Density = Mass / Volume
Density = 5.7 g / 0.3 ml

2. Simplify the calculation:
Density = 19 g/ml (as given in the question)

3. Compare the calculated density with the density of pure gold:
Since the calculated density (19 g/ml) is the same as the density of pure gold (19 g/ml), we can conclude that the ring is indeed made of real gold.

To determine if the gold ring is made of real gold, we need to compare its density with the known density of pure gold.

Density is defined as the mass of an object divided by its volume. Therefore, we can calculate the density of the gold ring using the given mass and volume.

Density = Mass / Volume

Given:
Mass of the gold ring = 5.7 grams
Volume of the gold ring = 0.3 ml

Density of the gold ring = 5.7 grams / 0.3 ml

To make the comparison, we need to convert the units so that the resulting density can be compared to the known density of gold.

The density of gold is given as 19 g/ml. So, to compare the densities effectively, we need to convert the given density of the gold ring into the same units.

Density of the gold ring (converted) = 5.7 grams / 0.3 ml * (1 ml / 1 cm^3)

The conversion factor (1 ml / 1 cm^3) is used because 1 ml is equivalent to 1 cm^3.

After the conversion, we can compare the density of the gold ring to the known density of gold.

If the density of the gold ring matches closely to the known density of gold (19 g/ml), then it can be considered to be made of real gold.

Indicate your subject in the "School Subject" box, so those with expertise in the area will respond to the question. This certainly is not physiology.