One liter of a gas mixture at 0 degree Celsius and 108.26 kPa contains 250 mg/L of H2S gas. Calculate the partial pressure exerted by gas.
Use PV = nRT and solve for P.
n = grams/molar mass.
16.7 kPa/l
To calculate the partial pressure exerted by H2S gas in the given mixture, we need to use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (in Pascals)
V = Volume (in cubic meters)
n = Number of moles
R = Ideal gas constant (8.314 J/(mol·K))
T = Temperature (in Kelvin)
First, let's convert the temperature from Celsius to Kelvin:
T(K) = T(°C) + 273.15
T(K) = 0 + 273.15
T(K) = 273.15 K
Next, let's convert the given volume from liters to cubic meters:
V(m^3) = V(L) / 1000
V(m^3) = 1 / 1000
V(m^3) = 0.001 m^3
To determine the number of moles of H2S gas, we need to convert the given concentration from mg/L to moles/m^3:
Concentration(moles/m^3) = Concentration(mg/L) * (1 g / 1000 mg) * (1 mol / molar mass of H2S)
Concentration(moles/m^3) = 250 * (1 g / 1000 mg) * (1 mol / 34.08 g/mol)
Concentration(moles/m^3) = 0.00733 mol/m^3
Now, we can rearrange the ideal gas law equation to solve for the pressure:
P = (nRT) / V
Substituting the known values:
P = (0.00733 mol/m^3) * (8.314 J/(mol·K)) * (273.15 K) / (0.001 m^3)
P ≈ 1.65 kPa
Therefore, the partial pressure exerted by the H2S gas in the gas mixture is approximately 1.65 kPa.
To calculate the partial pressure exerted by the H2S gas in the mixture, we can use the formula:
Partial Pressure (Pa) = (Concentration (mol/m^3)) * (Universal Gas Constant (R) * Temperature (K))
First, let's convert the given concentration from milligrams per liter (mg/L) to moles per cubic meter (mol/m^3).
Given:
Concentration of H2S gas (C) = 250 mg/L
Temperature (T) = 0 degree Celsius = 273.15 K (since temperature must be in Kelvin for the formula to work)
The molar mass of H2S is approximately 34.08 g/mol. Using this value, we can convert the concentration from mg/L to mol/m^3:
Concentration (C) = (250 mg/L) * (1 g/1000 mg) * (1 mol/34.08 g) * (1000 L/m^3)
= 7.33 mol/m^3
Next, we can substitute the values into the formula to calculate the partial pressure:
Partial Pressure (Pa) = (Concentration (mol/m^3)) * (Universal Gas Constant (R) * Temperature (K))
= (7.33 mol/m^3) * (8.314 J/(mol∙K)) * (273.15 K)
= 17,200 Pa
Therefore, the partial pressure exerted by the H2S gas in the mixture is 17,200 Pa.