The solubility of NaCl in water is 35.7 g NaCl/100 g H2O. Suppose that you have 500.0 g of NaCl. What is the minimum volume of water you would need to dissolve it all? The density of water is 1.0 g/mL.

100 grams H2O x (500/37.5) = about 1330 mL. Or look at it this way.

37.5 g NaCl/100 mL = 0.375 g NaCl/1 mL.
So (0.375 g NaCl/mL) x ??mL = 500 g
Solve for ??mL.

Well, let's see what we've got here. To find the minimum volume of water needed to dissolve all the NaCl, we can use the given solubility, which tells us that 100 g of water can dissolve 35.7 g of NaCl.

So, if we have 500.0 g of NaCl, we can set up a proportion to find the corresponding amount of water needed:

(500.0 g NaCl) / (35.7 g NaCl) = (x g H2O) / (100 g H2O)

Now we can cross multiply and solve for x:

500.0 g NaCl * 100 g H2O = 35.7 g NaCl * x g H2O

Dividing both sides by 35.7 g NaCl, we get:

100 * 500.0 / 35.7 = x

Approximately, x = 1402.52 g H2O.

But we need the minimum volume of water, so let's convert grams of water to milliliters by using the given density of water (1.0 g/mL):

1402.52 g H2O * (1 mL / 1 g) = 1402.52 mL.

So, the minimum volume of water required to dissolve all 500.0 g of NaCl is approximately 1402.52 mL of water. That's quite a thirst quencher, isn't it?

To find the minimum volume of water required to dissolve 500.0 g of NaCl, we need to use the solubility data provided.

The solubility of NaCl in water is given as 35.7 g NaCl/100 g H2O. This means that 100 g of water can dissolve 35.7 g of NaCl.

First, we need to calculate how much water can dissolve 500.0 g of NaCl using the given solubility data.

(500.0 g NaCl) x (100 g H2O / 35.7 g NaCl) = 1401.12 g H2O

We have found that 500.0 g of NaCl requires 1401.12 g of water to dissolve completely.

Next, we convert grams of water to volume (mL) using the density of water, which is 1.0 g/mL.

(1401.12 g H2O) x (1 mL / 1.0 g) = 1401.12 mL

Therefore, the minimum volume of water needed to dissolve 500.0 g of NaCl is 1401.12 mL.

To find the minimum volume of water needed to dissolve 500.0 g of NaCl, we need to use the solubility value given. The solubility of NaCl in water is 35.7 g NaCl per 100 g of water.

Step 1: Convert the mass of NaCl to the mass of water needed.
We know that the solubility of NaCl is 35.7 g NaCl per 100 g of water. So, to find the mass of water needed, we use the following calculation:

mass of water = (mass of NaCl / solubility of NaCl) * 100

mass of water = (500.0 g / 35.7 g/100 g) * 100

mass of water = 1401.96 g

Step 2: Convert the mass of water to volume.
We are given the density of water as 1.0 g/mL. So, to convert the mass of water to volume, we use the following calculation:

volume of water = mass of water / density of water

volume of water = 1401.96 g / 1.0 g/mL

volume of water = 1401.96 mL

Therefore, the minimum volume of water needed to dissolve 500.0 g of NaCl is 1401.96 mL.