When a volume of H2 reacts with an equal volume of Cl2 (assume you have 1 L of each) at the same temperature and pressure, what volume of product having the formula HCl is formed?

Question 4 answers

Start with the equation

Cl2 + H2 = 2HCl

so one mole of each forms 2 moles of HCl.

We know that number of moles is equivalent to volume. So 1 volume of each forms 2 volumes of HCl (equal volumes of gases contain the same number of moles under the same conditions).

Well, when H2 and Cl2 get together, it's like a chemistry party! But instead of dancing and mingling, they decide to combine and form HCl. It's like a chemical match made in heaven!

Now, since we have equal volumes of H2 and Cl2 (1 L each), we have a balanced gathering of molecules. When they react, they combine in a 1:1 ratio to form HCl.

So, for every 1 L of H2, we'll end up with 1 L of HCl. It's a perfect volume-matching game! It's like dating, but for gases.

Therefore, the volume of product formed having the formula HCl would also be 1 liter. So let the chemical party begin!

To determine the volume of product formed, you need to consider the balanced chemical equation for the reaction between H2 and Cl2:

H2 + Cl2 -> 2HCl

According to the balanced equation, 1 mole of H2 reacts with 1 mole of Cl2 to form 2 moles of HCl.

Given that you have 1 L of each reactant gas at the same temperature and pressure, you can assume that the volume of gases is directly proportional to the number of moles. Therefore, the initial volume of H2 and Cl2 is 1 L each.

Since the reaction consumes an equal volume of both gases, only half of the initial volume will be consumed. Thus, the volume of reactants consumed is 0.5 L of H2 and 0.5 L of Cl2.

According to the stoichiometry of the balanced equation, for every 2 moles of HCl produced, 1 mole of H2 is consumed. Therefore, the volume of HCl produced is also half of the initial volume, which is 0.5 L.

So, when 1 L of H2 reacts with an equal volume of Cl2, 0.5 L of product HCl is formed.

To determine the volume of HCl formed when equal volumes of H2 and Cl2 react, we need to first understand the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between H2 and Cl2 to form HCl is:

H2 + Cl2 → 2HCl

According to the balanced equation, for every 1 mole of H2 and 1 mole of Cl2 that react, 2 moles of HCl are produced.

Given that we have equal volumes of H2 and Cl2 (1 L each), we can assume that they are at the same number of moles, as gases at the same temperature and pressure have equal volumes.

So, we have 1 mole of H2 reacting with 1 mole of Cl2, which means we will produce 2 moles of HCl.

To convert moles to volume, we need to use the ideal gas law equation:

V = nRT/P

Where:
V is the volume
n is the number of moles
R is the ideal gas constant (0.0821 L·atm/(mol·K))
T is the temperature in Kelvin
P is the pressure in atmospheres

Since the temperature and pressure are not provided in the question, let's assume they are constant.

To simplify the calculation, let's assume the temperature is 273.15 Kelvin (0 Celsius) and the pressure is 1 atmosphere.

Using the ideal gas law equation, we can calculate the volume of HCl formed:

V(HCl) = 2 moles × (0.0821 L·atm/(mol·K)) × 273.15 K / 1 atm

V(HCl) = 44.95 L

Therefore, when 1 L of H2 reacts with 1 L of Cl2 at the same temperature and pressure, the volume of HCl formed is approximately 44.95 L.