calculate the amount of heat energy required to raise the temperature of a 5kg block of solid platinum from 0 degrees celsius to 25 degrees celsius. the specific heat of platinum is 133j/kg k. how much heat energy is required to raise 5kg of water by the same amount? the specific heat of water is 4.2kk/kg k
Heat energy required = Q
= (Mass)*(Specific Heat)*(Temperature rise)
It is often written M*C*(delta T)
For platinum, the answer is 5*25*133 = 17,000 J (rounded to two significant figures)
Now do water.
525
which abosbs heat faster steel or ice
what is the sl unit of heat capacity?
To calculate the amount of heat energy required to raise the temperature of a substance, you can use the specific heat formula:
Q = m * c * ΔT
Where:
Q = heat energy (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius or Kelvin)
ΔT = change in temperature (in degrees Celsius or Kelvin)
Let's calculate the heat energy required to raise the temperature of the platinum block:
m = 5 kg (mass of the platinum block)
c = 133 J/kg*K (specific heat capacity of platinum)
ΔT = 25°C - 0°C = 25 K (change in temperature)
Q = 5 kg * 133 J/kg*K * 25 K = 16,625 J
Therefore, the amount of heat energy required to raise the temperature of the 5 kg block of solid platinum from 0°C to 25°C is 16,625 joules (J).
Now let's calculate the heat energy required to raise the temperature of 5 kg of water by the same amount:
m = 5 kg (mass of the water)
c = 4.2 kJ/kg*K (specific heat capacity of water)
ΔT = 25°C - 0°C = 25 K (change in temperature)
Since the specific heat capacity of water is given in kilojoules, we need to convert it to joules:
c = 4.2 kJ/kg*K * 1000 J/kJ = 4200 J/kg*K
Q = 5 kg * 4200 J/kg*K * 25 K = 525,000 J
Therefore, the amount of heat energy required to raise the temperature of 5 kg of water from 0°C to 25°C is 525,000 joules (J).