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a ball is thrown at an initial angle of 37 and initail velocity of 23.0 m/s reaches a maximum height h, as shwon in the Figure. With what initial speed must a ball be thrown straight up to reach the same maximum height h?

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2 answers
  1. Vi^2=2gh

    Vi= sqrt (2gh)

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    bobpursley
  2. sin(37) * 23 = 13.8

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