A 22.5 gram sample of ammonium carbonate contains ? mol of ammonium ions?

0.468

0.9

2.14 trust

To find the number of moles of ammonium ions in a 22.5 gram sample of ammonium carbonate, we need to use the molar mass and the chemical formula of ammonium carbonate.

The chemical formula of ammonium carbonate is (NH4)2CO3.

Let's break down the formula to find the molar mass:
- Ammonium (NH4) ion has a molar mass of 18.04 g/mol (1 nitrogen atom with a molar mass of 14.01 g/mol and 4 hydrogen atoms with a total molar mass of 4.03 g/mol).
- Carbonate (CO3) ion has a molar mass of 60.01 g/mol (1 carbon atom with a molar mass of 12.01 g/mol and 3 oxygen atoms with a total molar mass of 48.00 g/mol).

Now, calculate the molar mass of ammonium carbonate:
(2 x molar mass of ammonium ion) + molar mass of carbonate ion
= (2 x 18.04 g/mol) + 60.01 g/mol
= 36.08 g/mol + 60.01 g/mol
= 96.09 g/mol

Now, we can calculate the number of moles of ammonium ions in the 22.5 gram sample using the molar mass and the formula:
moles = mass (g) / molar mass (g/mol)
= 22.5 g / 96.09 g/mol

Calculating this gives us the result:
moles = 0.2343 mol

Therefore, a 22.5 gram sample of ammonium carbonate contains approximately 0.2343 moles of ammonium ions.

figure the mole mass of (

NH4)2CO3
add two N, 8 H, one C, 3 O