How many moles of H+(aq) ions are present in 1.25 L of 0.75M Nitric Acid?
A. 0.60 mol
B. 0.75 mol
C. 0.94 mol
D. 1.7 mol
E. 1.9 mol
Please show me how to work this!
Pls do your job so students don't have to cheat.
To calculate the number of moles of H+(aq) ions in a solution of nitric acid, you need to multiply the volume of the solution by the molarity of H+(aq) ions.
Given:
Volume of the solution (V) = 1.25 L
Molarity of H+(aq) ions (M) = 0.75M
Using the formula:
moles = molarity × volume
Substituting the given values:
moles = 0.75M × 1.25 L = 0.938 mol
Therefore, the correct answer is option C: 0.94 mol.
To find the number of moles of H+(aq) ions in the solution, you need to use the given molarity (0.75M) and volume (1.25 L) of the nitric acid.
The formula to find the number of moles is:
moles = molarity × volume
Substituting the given values:
moles = 0.75M × 1.25 L
Multiply the molarity (0.75) by the volume (1.25):
moles = 0.9375 mol
Since the value is given to three significant figures (0.9375), you round it to two decimal places:
moles ≈ 0.94 mol
Therefore, the answer is C. 0.94 mol.
moles of HNO3= volume*molarity
and, it commpletely dissocates, so..
moles Hions=molesHNO3