What is the molarity of ZnCl2 that forms when 30.0g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 285 mL.
Zn(s) + CuCl2(aq)--> ZnCl2(aq) + Cu(s)
Please Explain!! Thanks!!
1.80
M
To find the molarity of ZnCl2, we first need to determine the number of moles of ZnCl2 produced in the reaction.
1. Find the number of moles of Zn:
To do this, we need to use the molar mass of zinc (Zn), which is 65.38 g/mol.
Number of moles of Zn = Mass of Zn / Molar mass of Zn
Number of moles of Zn = 30.0 g / 65.38 g/mol
Number of moles of Zn = 0.458 moles
2. Use the stoichiometry of the balanced equation to determine the number of moles of ZnCl2 produced:
From the balanced equation, we can see that the ratio of Zn to ZnCl2 is 1:1.
Therefore, the number of moles of ZnCl2 produced is also 0.458 moles.
3. Calculate the molarity of ZnCl2:
Molarity is defined as moles of solute per liter of solution.
Molarity = Number of moles of ZnCl2 / Volume of solution (in liters)
We need to convert the volume of solution from milliliters to liters:
Volume of solution = 285 mL * (1 L / 1000 mL)
Volume of solution = 0.285 L
Molarity = 0.458 moles / 0.285 L
Molarity = 1.60 M
Therefore, the molarity of ZnCl2 that forms when 30.0g of zinc completely reacts with CuCl2 is 1.60 M.
To find the molarity of ZnCl2, we need to first calculate the number of moles of ZnCl2 formed when the given amount of zinc reacts with CuCl2. Then, we can divide the moles of ZnCl2 by the volume in liters to get the molarity.
1. Calculate the number of moles of zinc (Zn):
Molar mass of Zn = 65.38 g/mol (from the periodic table)
Moles of Zn = mass of Zn / molar mass of Zn
= 30.0 g / 65.38 g/mol
2. Based on the balanced equation, Zn reacts with CuCl2 in a 1:1 ratio. This means that one mole of Zn reacts with one mole of CuCl2 to produce one mole of ZnCl2.
3. Calculate the number of moles of ZnCl2 formed:
Moles of ZnCl2 = moles of Zn
4. Convert the given volume to liters:
Volume = 285 mL = 285 mL * (1 L / 1000 mL)
5. Calculate the molarity of ZnCl2:
Molarity (M) = Moles of ZnCl2 / Volume
Putting it all together, the molarity of ZnCl2 can be found by dividing the moles of ZnCl2 (which is equal to the moles of Zn) by the volume in liters.