I'm having trouble with molarity. What is the molarity of a KCl solution made by diluting 75.0 mL of a 0.200 M solution to a final volume of 100.0 mL?
The molarity will be inversley proportional to the change in volume.
M= 75/100 * .2M
.15 M
To find the molarity of a solution after dilution, you can use the formula:
Molarity1 x Volume1 = Molarity2 x Volume2
Where:
Molarity1 = Initial molarity of the solution
Volume1 = Initial volume of the solution
Molarity2 = Final molarity of the solution
Volume2 = Final volume of the solution
In this case, you have a 0.200 M KCl solution and you want to dilute it to a final volume of 100.0 mL. The initial volume is 75.0 mL. Let's substitute the values into the formula:
0.200 M x 75.0 mL = Molarity2 x 100.0 mL
Now we can solve for Molarity2:
0.200 M x 75.0 mL / 100.0 mL = Molarity2
Molarity2 = 0.150 M
Therefore, the molarity of the KCl solution after dilution is 0.150 M.
To determine the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, you are given the initial volume and concentration of the solution, as well as the final volume of the diluted solution.
First, let's calculate the amount of solute (in moles) in the initial solution. The formula to calculate the amount of solute is:
moles = concentration (M) × volume (L)
So, in this case, the initial volume is 75.0 mL (or 0.075 L) and the initial concentration is 0.200 M. Let's substitute these values into the formula:
moles = 0.200 M × 0.075 L
moles = 0.015 mol
So, there are 0.015 moles of KCl in the initial solution.
Next, we need to calculate the final volume of the diluted solution in liters. The final volume given is 100.0 mL (or 0.100 L).
Now, we can use the formula for molarity:
Molarity = moles of solute / volume of solution
Molarity = 0.015 mol / 0.100 L
Molarity = 0.150 M
Therefore, the molarity of the KCl solution, made by diluting 75.0 mL of a 0.200 M solution to a final volume of 100.0 mL, is 0.150 M.