I need major help im not understanding this at all:
Complete and balance each of the following equations for acid-base reactions. (Type your answer using the format CO2 for CO2 and Al(OH)3 for Al(OH)3. Use the lowest possible coefficients.)
HBr(aq) + LiOH(aq) -> find this compound(aq) + find this compound (l)
thought acid-base reactions had to have H20 so i put H20 for the first and LiBr for the other one but it was wrong
LiBr(aq) and H2O(l) are correct.
To complete and balance the given acid-base equation, we need to first identify the products formed from the reaction between HBr (hydrobromic acid) and LiOH (lithium hydroxide).
In an acid-base reaction between a strong acid and a strong base, the products are typically water (H2O) and a salt. A salt is formed by the combination of the cation from the base with the anion from the acid.
In this case, the cation from LiOH is Li+ and the anion from HBr is Br-. Therefore, the product is LiBr, which is a neutral salt.
Now let's complete and balance the equation:
HBr(aq) + LiOH(aq) -> H2O + LiBr
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
Considering the number of bromine (Br) atoms, we have 1 on the left and 1 on the right side of the equation, so it is already balanced.
Next, let's balance the hydrogen (H) and oxygen (O) atoms by adding coefficients:
2HBr(aq) + 2LiOH(aq) -> H2O + LiBr
Now, the equation is balanced with 2 hydrogen atoms and 2 oxygen atoms on both sides.
Therefore, the balanced equation for the reaction between HBr and LiOH is:
2HBr(aq) + 2LiOH(aq) -> H2O + LiBr
Make sure to double-check the coefficients to ensure all elements are balanced.