calculate the weight of crystal formed on cooling 80 gm of saturated solution from 60 degree Celsius to 30 degree Celsius. solubility of salt at 60 degree Celsius and 30 degree Celsius are 132 and 95 respectively.
To calculate the weight of the crystal formed, we need to determine the amount of solute that comes out of the saturated solution when it is cooled from 60°C to 30°C.
Step 1: Calculate the amount of solute in the saturated solution at 60°C.
The solubility of salt at 60°C is 132g. Since the solution is saturated, it means we have 132g of salt dissolved in the solution.
Step 2: Calculate the amount of solute in the saturated solution at 30°C.
The solubility of salt at 30°C is 95g. Since we started with a saturated solution and cooled it down, the amount of solute that can remain dissolved decreases. From the solubility values, we can see that at 30°C, only 95g of salt can remain dissolved.
Step 3: Calculate the difference in solute between the two temperatures.
The difference in solute between the two temperatures is given by:
Amount of solute at 60°C - Amount of solute at 30°C
= 132g - 95g
= 37g
Step 4: Calculate the weight of the crystal formed.
The weight of the crystal formed is equal to the amount of solute that comes out of the solution when it cools down. Therefore, the weight of the crystal formed is 37g.
To calculate the weight of the crystal formed, we'll use the concept of solubility and the change in temperature.
First, we need to find the amount of salt dissolved in the solution at both temperatures:
Step 1: Calculate the amount of salt dissolved at 60°C
Given: Solubility at 60°C = 132 g
Step 2: Calculate the amount of salt dissolved at 30°C
Given: Solubility at 30°C = 95 g
Step 3: Calculate the difference in the amount of salt dissolved:
ΔSolubility = Solubility at 60°C - Solubility at 30°C
Step 4: Calculate the amount of salt precipitated (crystal formed):
Amount of precipitated salt = Solubility at 60°C - ΔSolubility
Finally, we can calculate the weight of the crystal formed by subtracting the amount of salt remaining in the solution from the initial amount of salt:
Weight of the crystal formed = Initial weight of the solution - Amount of salt remaining in solution
Let's plug in the given values to find the weight of the crystal formed:
Initial weight of the solution = 80 g
Solubility at 60°C = 132 g
Solubility at 30°C = 95 g
Step 1: Calculate the amount of salt dissolved at 60°C:
Amount of salt dissolved at 60°C = Solubility at 60°C = 132 g
Step 2: Calculate the amount of salt dissolved at 30°C:
Amount of salt dissolved at 30°C = Solubility at 30°C = 95 g
Step 3: Calculate the difference in the amount of salt dissolved:
ΔSolubility = 132 g - 95 g = 37 g
Step 4: Calculate the amount of salt precipitated:
Amount of precipitated salt = Solubility at 60°C - ΔSolubility = 132 g - 37 g = 95 g
Finally, calculate the weight of the crystal formed:
Weight of the crystal formed = Initial weight of the solution - Amount of salt remaining in solution
Weight of the crystal formed = 80 g - 95 g = -15 g
Therefore, the weight of the crystal formed is -15 g. However, it is not possible to have negative weight, so it is likely a calculation error or the given data is incorrect. Please double-check your values and calculations.
Answer
132 WHAT and 95 WHAT? If that is 132 grams of solution and 95 grams of solution, then you do it this way.
grams salt in 80 g soln at 60 C is
132 x (80/100) = about 106 but you need to do that more accurately.
When cooled to 30 C it will dissolve
95 x (80/100) = about 74 (more accuracy needed).
How much will ppt? 106-74 (or whatever your numbers turn out to be).