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If the ball is released from rest at a height of 0.64 m above the bottom of the track on the no-slip side, what is its angular speed when it is on the frictionless side of the track?Assume the ball is a solid sphere of radius 4.0 cm and mass 0.14 kg

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  1. Applying law of conservation of energy:
    P.E at height h = sum of translational and rotational K.E
    mgh=1/2mv^2 +1/2Iw^2
    but v=wr
    I =moment of inertia.
    =2/5mr^2
    i hope u have get the concept Sarah

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