A father's age is 3 times his son's age. Sum of their ages is 44 years. Find their ages.
Why not just stick with one variable.
son's age --- x
father's age -- 3x , it said so
x+3x = 44
x = 11 --son
3x = 33 -- father
let x be the father's age and y be the son's age..
x= 3times the age of son
x=3y
father's age{x) + son's age (y) = 44
now we have these
x=3y
x+y =44
substitute x with 3y for the 2nd equation
so we now we have 3y+y=44
u can solve this from here.
after getting the y(the son's age) you can find the dad's (x) age by myltiply the son's age by 3 ..GOODLUCK :)
Let's assign variables to represent the unknowns. Let:
- x be the father's age
- y be the son's age
According to the information provided, we have two equations:
1) "A father's age is 3 times his son's age":
x = 3y
2) "Sum of their ages is 44 years":
x + y = 44
To find their ages, we need to solve this system of equations. Substituting x in the second equation with its equivalent value from the first equation, we get:
3y + y = 44
4y = 44
y = 11
Now, substituting the found value of y back into the first equation:
x = 3 * 11
x = 33
Therefore, the father is 33 years old and the son is 11 years old.
To find the father's and son's ages, we can set up a system of equations based on the given information.
Let's represent the son's age as "x" and the father's age as "3x".
We have two equations:
1) The father's age is 3 times the son's age: 3x = father's age
2) The sum of their ages is 44 years: x + 3x = 44
Now, let's solve the system of equations:
From equation 2, we can simplify it to 4x = 44.
Dividing both sides of the equation by 4, we get x = 11.
Substituting this value back into equation 1, we find that the father's age is 3 * 11 = 33.
Therefore, the son's age is 11 years, and the father's age is 33 years.