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A mass sitting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. 1.0 J of work is required to compress the spring by 0.12 m. If the mass is released from rest with the spring compressed, it experiences a maximum acceleration of 16 m/s2

find the value of spring constant

find value of the mass

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2 answers

  1. force=ma=kx

    k= m*a/x

    but work= 1/2 kx^2
    k=2*work/x^2

    Use the second first to get k, then

    a=kx/m

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  2. 2(1)/.12^2=138.88888888889=138.9N/m
    F=kx = mg=kx => ma=kx => m=kx/a
    (138.9(.12))/16 = 1.04kg

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