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a 20 kg loudspeaker is suspended 2m below a ceiling by two 3m-long cables that angle outward at equal angles. what is the tension in the cables?

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3 answers
  1. The amount of angle is important.

    Use symettry, each cable is holding half the weight.

    measuring the angle between the vertical and the cable, then 1/2 mg=Tension*cosTheta where theta is from the vertical to a cable.

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    bobpursley
  2. i got the answer by
    (2m/3m)=0.666
    sin-1(0.666)=41.8 degrees
    to find tension
    T=Fg/2sin(theta)
    20kg*9.8=196N
    2sin(41.8)=1.333
    196N/1.3333=147N

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  3. jkj;l

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