AgNO3+NaOH-->AgOH+NaNO3
give me molecular , total ionic and net ionic???"
You put the (aq) [for aqueous] in.
Ag^+ + NO3^- + Na^+ + OH^- ==> AgOH(s) + Na^+ + NO3^-
For the net ionic, cancel thos ionx common to both sides.
Ag^+(aq) + OH^-(aq) ==> AgOH(s)
Molecular equation: AgNO3 + NaOH ⟶ AgOH + NaNO3
Ionic equation:
Ag+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) ⟶ AgOH(s) + Na+(aq) + NO3-(aq)
Net ionic equation:
Ag+(aq) + OH-(aq) ⟶ AgOH(s)
The balanced chemical equation for the reaction between AgNO3 and NaOH is:
AgNO3 + NaOH → AgOH + NaNO3
Here are the molecular, total ionic, and net ionic equations:
1. Molecular equation:
AgNO3 + NaOH → AgOH + NaNO3
2. Total ionic equation:
Ag⁺ + NO₃⁻ + Na⁺ + OH⁻ → AgOH + Na⁺ + NO₃⁻
3. Net ionic equation:
Ag⁺ + OH⁻ → AgOH
To find the molecular, total ionic, and net ionic equations for the given chemical reaction, you need to first understand the concept of chemical equations and how to balance them.
Step 1: Write the balanced molecular equation.
The given chemical equation is:
AgNO3 + NaOH → AgOH + NaNO3
To balance this equation, you need to make sure that the number of atoms of each element is the same on both sides. The balanced molecular equation for this reaction is:
AgNO3 + NaOH → AgOH + NaNO3
Step 2: Write the total ionic equation.
In a total ionic equation, all soluble compounds are dissociated into their ions. The insoluble compounds remain unchanged. Determine the solubility of each compound to determine which compounds will dissociate.
AgNO3 (silver nitrate) is a soluble ionic compound and dissociates completely into Ag+ (silver cation) and NO3- (nitrate anion) ions.
NaOH (sodium hydroxide) is also a soluble compound and dissociates into Na+ (sodium cation) and OH- (hydroxide anion) ions.
AgOH (silver hydroxide) is considered insoluble and does not dissociate into ions.
NaNO3 (sodium nitrate), like the previous compounds, is soluble and dissociates into Na+ and NO3- ions.
The total ionic equation for this reaction is:
Ag+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) → AgOH(s) + Na+(aq) + NO3-(aq)
Step 3: Write the net ionic equation.
The net ionic equation includes only the species that change during the reaction. In this case, the Ag+ and OH- ions react to form AgOH.
The net ionic equation for this reaction is:
Ag+(aq) + OH-(aq) → AgOH(s)
To summarize:
Molecular equation: AgNO3 + NaOH → AgOH + NaNO3
Total ionic equation: Ag+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) → AgOH(s) + Na+(aq) + NO3-(aq)
Net ionic equation: Ag+(aq) + OH-(aq) → AgOH(s)