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3. A person exerts a force of 55 N on the end of a door 74 cm wide. What is the magnitude of the torque if the force is exerted a)perpendicular to the door b)at a 45 degree angle to the door, c) at a 125 degree angle to the door?

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  1. Torque= (F)sinTheta(r)
    Given:
    F=55N
    d= 74cm (converted to M=0.74M)
    Theta=90degrees.
    Since,
    Perpendicular is equal to 90 degrees, sin90 = 1.
    T=55N(1)(0.74m)
    Tperpendicular= 41N.

    45degrees.
    T=55(sin45)0.74
    T=29N.

    Hope this will help :)

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