Two strong magnets on opposite sides of a small table are shown. The long-range attractive force between the magnets keeps the lower magnet in place. Suppose the weight of the table is 19.7 N, the weight of each magnet is 4.17 N, and the magnetic force on the lower magnet is 5.39 times its weight. Find the magnitude of the force of the lower magnet on the upper magnet.
Well, well, well! Looks like we've got ourselves a little magnet mystery here! Don't worry, I'll use my magnetic personality to give you the answer you're looking for!
Let's break this down. We know that the weight of the table is 19.7 N, and each magnet weighs 4.17 N. The magnetic force on the lower magnet is 5.39 times its weight.
So, first, we need to find the weight of the lower magnet. If the weight of the magnet is 4.17 N, then when we multiply it by 5.39, we get 22.48 N. That's the force acting on the lower magnet.
Now, for the big reveal! The question asks for the magnitude of the force of the lower magnet on the upper magnet. Since we know the weight of the lower magnet, which is 22.48 N, and we're dealing with two magnets of equal weight, we can simply DOUBLE that force!
So, the magnitude of the force of the lower magnet on the upper magnet is 2 times 22.48 N, which gives us a dazzling result of 44.96 N!
There you have it! The force of the lower magnet on the upper magnet is 44.96 N. I hope I've magnetized you with my humor and answered your question!
To find the magnitude of the force of the lower magnet on the upper magnet, we need to first find the weight of the lower magnet.
Since the magnetic force on the lower magnet is 5.39 times its weight, we can calculate the weight of the lower magnet by dividing the magnetic force by 5.39.
Weight of the lower magnet = Magnetic force / 5.39
Weight of the lower magnet = 4.17 N / 5.39 = 0.773 N (approximately)
Now that we know the weight of the lower magnet, we can find the net force acting on it. The net force on the lower magnet is equal to the weight of the table plus the weight of the two magnets:
Net force on the lower magnet = Weight of the table + 2 * Weight of the magnet
Net force on the lower magnet = 19.7 N + 2 * 4.17 N
Net force on the lower magnet = 19.7 N + 8.34 N = 27.04 N
Now, since the lower magnet is kept in place by the long-range attractive force, the force of the lower magnet on the upper magnet must be equal in magnitude and opposite in direction to the net force on the lower magnet.
Therefore, the magnitude of the force of the lower magnet on the upper magnet is 27.04 N.