Michael Jordan was said to have a hang time of 3 seconds. Use kinematic equations to determine the height to which MJ could leap if he had a hang time of 3 seconds. Hint: You are solving for distance!

Well, at the top, it took 1.5 seconds to come down.

h=1/2 g t^2 where g=9.9m/s^2 and t=1.5
h= 1/2 9.8 * 2.25
I don't believe the time unless it was slow motion.

It’s 11.25 trust me. (If 10 is Acceleration) Bobs is also right.

Need proof just write
H=1/2 (10*2.25)

3 seconds

Well, let me juggle these kinematic equations for a moment. Hang on tight!

To determine the height Michael Jordan could leap, we can use the following equation:

h = (1/2) * g * t^2

where:
h is the height,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
and t is the hang time.

Plugging in the values, we have:

h = (1/2) * 9.8 * (3^2)
h = (1/2) * 9.8 * 9
h = 44.1 meters

So, if the reports are correct, Michael Jordan could leap up to a height of approximately 44.1 meters! That's one high-flying clown!

To determine the height to which Michael Jordan could leap if he had a hang time of 3 seconds, we can use the kinematic equations of motion. Specifically, we will use the equation for vertical displacement.

The equation for displacement of an object in free fall is given by:

y = u * t + (1/2) * a * t^2,

where:
y is the vertical displacement (height),
u is the initial vertical velocity,
t is the time,
and a is the acceleration due to gravity (approximately -9.8 m/s^2).

In this case, Michael Jordan's hang time is given as 3 seconds, so we will substitute t = 3 into the equation. Let's assume that Michael Jordan's initial vertical velocity (u) is 0, meaning he starts from rest.

Thus, the equation becomes:

y = 0 * 3 + (1/2) * (-9.8) * (3^2).

Simplifying the equation:

y = 0 + (-4.9) * 9,

y = -44.1 m.

Therefore, the height to which Michael Jordan could leap with a hang time of 3 seconds is approximately 44.1 meters.

11.1m