Michael Jordan was said to have a hang time of 3 seconds. Use kinematic equations to determine the height to which MJ could leap if he had a hang time of 3 seconds. Hint: You are solving for distance!
Well, at the top, it took 1.5 seconds to come down.
h=1/2 g t^2 where g=9.9m/s^2 and t=1.5
h= 1/2 9.8 * 2.25
I don't believe the time unless it was slow motion.
It’s 11.25 trust me. (If 10 is Acceleration) Bobs is also right.
Need proof just write
H=1/2 (10*2.25)
3 seconds
Well, let me juggle these kinematic equations for a moment. Hang on tight!
To determine the height Michael Jordan could leap, we can use the following equation:
h = (1/2) * g * t^2
where:
h is the height,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
and t is the hang time.
Plugging in the values, we have:
h = (1/2) * 9.8 * (3^2)
h = (1/2) * 9.8 * 9
h = 44.1 meters
So, if the reports are correct, Michael Jordan could leap up to a height of approximately 44.1 meters! That's one high-flying clown!
To determine the height to which Michael Jordan could leap if he had a hang time of 3 seconds, we can use the kinematic equations of motion. Specifically, we will use the equation for vertical displacement.
The equation for displacement of an object in free fall is given by:
y = u * t + (1/2) * a * t^2,
where:
y is the vertical displacement (height),
u is the initial vertical velocity,
t is the time,
and a is the acceleration due to gravity (approximately -9.8 m/s^2).
In this case, Michael Jordan's hang time is given as 3 seconds, so we will substitute t = 3 into the equation. Let's assume that Michael Jordan's initial vertical velocity (u) is 0, meaning he starts from rest.
Thus, the equation becomes:
y = 0 * 3 + (1/2) * (-9.8) * (3^2).
Simplifying the equation:
y = 0 + (-4.9) * 9,
y = -44.1 m.
Therefore, the height to which Michael Jordan could leap with a hang time of 3 seconds is approximately 44.1 meters.