the speed of a cyclist reduces uniformly from 2.5 m/s to 1.0 m/s in 12 s.

(a) calculate the deceleration of the cyclist.
(b) calculate the distance travelled by the cyclist in this time

a) Acceleration or deceleration = Final velocity - initial velocity / Time taken

D = 1-2.5 / 12
D= -0.125

b) d = ½×(Vi + Vf) × t
where
d = displacement = ?
Vf = final velocity = 1 m/s
Vi = initial velocity = 2.5 m/s
t = time = 12 s
so
d = ½×(2.5 + 1) × 12
d = 21 m

This is best explanation for a student to understand

Why did the cyclist slow down? Because it's hard to pedal with a glass of lemonade in one hand! Now, let's solve these equations.

(a) To find the deceleration, we can use the formula: acceleration = (final velocity - initial velocity) / time taken. Plugging in the values, we get: acceleration = (1.0 m/s - 2.5 m/s) / 12 s. Simplifying this gives us: acceleration = -1.5 m/s² / 12 s.

(b) To find the distance traveled, we can use the formula: distance = (initial velocity + final velocity) / 2 * time taken. Plugging in the values, we get: distance = (2.5 m/s + 1.0 m/s) / 2 * 12 s. Simplifying this gives us: distance = 3.5 m/s / 2 * 12 s.

Now you can use your mathematical skills to calculate the deceleration and distance.

To calculate the deceleration of the cyclist, we can use the formula:

deceleration = (final velocity - initial velocity) / time

Given:
Initial velocity (u) = 2.5 m/s
Final velocity (v) = 1.0 m/s
Time (t) = 12 s

(a) Calculating the deceleration:
deceleration = (1.0 m/s - 2.5 m/s) / 12 s

Simplifying the equation:
deceleration = (-1.5 m/s) / 12 s
deceleration = -0.125 m/s²

The deceleration of the cyclist is -0.125 m/s².

(b) To calculate the distance travelled by the cyclist, we can use the equation of motion:

distance = (initial velocity + final velocity) / 2 * time

Given:
Initial velocity (u) = 2.5 m/s
Final velocity (v) = 1.0 m/s
Time (t) = 12 s

Calculating the distance:
distance = (2.5 m/s + 1.0 m/s) / 2 * 12 s

Simplifying the equation:
distance = 3.5 m/s / 2 * 12 s
distance = 42 m

The distance travelled by the cyclist in this time is 42 meters.

Sol

Accelaration=F.V-I.V/TIME TAKEN
NOW WE CAN SAY THAT,
a=0-2.5/12
a=-2.5/12
a=0.2083