Dylan has $2.30 in dimes and nickels. The dimes exceed nickels by 5. Find the# of each kind.
let x= nickels=
Let x+5= dimes=
2.3=(.05)x+(.10)x+5
2.3= .05x+.10x+5.1
2.3=.15x+5.1
-2.8= .15x
-18.666666666repeating=x
what did i do wrong?
You forgot confused the parentheses.
2.3 = .05x + .10(x + 5)
2.3 = .05x + .10x +.50
1.8 = .15x
12 = x
I hope this helps. Thanks for asking.
jesus christ 2007..
ikr
In your equation, you have correctly defined x as the number of nickels. However, you made a mistake when defining the number of dimes. You stated that x + 5 is equal to the number of dimes, but it should be x + 5 is equal to the excess of dimes over nickels.
To correct this, let's redefine the variables:
Let x = number of nickels
Let x + 5 = excess of dimes over nickels
Now, let's set up the equation again:
The value of the nickels can be calculated as 0.05x since each nickel is worth $0.05.
The value of the dimes can be calculated as 0.10(x + 5) since each dime is worth $0.10 and there is an excess of 5 dimes over nickels.
The total value of the coins is $2.30, so we can set up the equation:
0.05x + 0.10(x + 5) = 2.30
Simplifying the equation:
0.05x + 0.10x + 0.50 = 2.30
Combining like terms:
0.15x + 0.50 = 2.30
Next, subtract 0.50 from both sides of the equation:
0.15x = 2.30 - 0.50
Simplifying:
0.15x = 1.80
Finally, divide both sides of the equation by 0.15 to solve for x:
x = 1.80 / 0.15
x = 12
So there are 12 nickels and 12 + 5 = 17 dimes.