A solution of ethanol (C2H5OH) in water is prepared by dissolving 61.9 mL of ethanol (density = 0.79 g/cm3) in enough water to make 250.0 mL of solution. What is the molarity of the ethanol in this solution?
Mass=vxd=61.9mlx0.79ml=48.9g since we have found mass then moles=48.9g/46.08 g/mol=1.06mol since we have found the number of moles then we can find the conc. Of ethanol in 250mL which is molarity=moles / volume=1.06mol/0.250l=4.24mol/L
grams ethanol = volume x density.
moles ethanol = grams/molar mass.
M = moles/0.250 L = ??
Wi is the molarity of ethanol (c2h50h)
Why did the ethanol go to the party? Because it knew it would make the solution a lot more interesting!
To find the molarity of the ethanol in the solution, we first need to calculate the mass of ethanol in grams. We can do this by multiplying the density of ethanol by its volume.
Density of ethanol = 0.79 g/cm³
Volume of ethanol = 61.9 mL
Mass of ethanol = Density × Volume
= 0.79 g/cm³ × 61.9 mL
≈ 48.841 g
Now, we can calculate the molarity (M) of the ethanol using the following formula:
Molarity (M) = moles of solute / volume of solution (in L)
To find the moles of ethanol, we need to divide the mass of ethanol by its molar mass.
Molar mass of ethanol (C2H5OH) = (2 × atomic mass of C) + (6 × atomic mass of H) + atomic mass of O
Atomic mass of C = 12.011 g/mol
Atomic mass of H = 1.008 g/mol
Atomic mass of O = 16.00 g/mol
Molar mass of ethanol = (2 × 12.011) + (6 × 1.008) + 16.00
= 46.068 g/mol
Now, let's calculate the moles of ethanol:
Moles of ethanol = mass of ethanol / molar mass
= 48.841 g / 46.068 g/mol
≈ 1.060 mol
Finally, we can calculate the molarity of ethanol in the solution:
Molarity (M) = moles of solute / volume of solution (in L)
= 1.060 mol / 0.250 L
≈ 4.24 M
So, the molarity of ethanol in this solution is approximately 4.24 M. Cheers!
To find the molarity of the ethanol in the solution, we need to determine the number of moles of ethanol and the volume of the solution.
First, let's calculate the mass of ethanol using its density and volume:
Mass = Density × Volume
Mass = 0.79 g/cm^3 × 61.9 mL = 48.9 g
Next, we'll convert the mass of ethanol to moles using its molar mass. The molar mass of ethanol (C2H5OH) can be calculated by summing the atomic masses:
Molar Mass of C2H5OH = 2 × Molar Mass of C + 6 × Molar Mass of H + Molar Mass of O
Molar Mass of C2H5OH = 2 × 12.01 g/mol + 6 × 1.01 g/mol + 16.00 g/mol
Molar Mass of C2H5OH = 46.07 g/mol
Moles of Ethanol = Mass of Ethanol / Molar Mass of C2H5OH
Moles of Ethanol = 48.9 g / 46.07 g/mol ≈ 1.06 mol
Lastly, we calculate the molarity of the ethanol by dividing the number of moles of ethanol by the volume of the solution (in liters):
Molarity (M) = Moles of Ethanol / Volume of Solution (in L)
Molarity (M) = 1.06 mol / 0.250 L ≈ 4.24 M
Therefore, the molarity of the ethanol in this solution is approximately 4.24 M.