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A projectile is fired at an upward angle of 45 degrees from the top of a 265 m cliff with a speed of 350 m/s. What will be it's speed when it strikes the ground below?

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3 answers
  1. the initial energy is 1/2 m v^2 + mgh

    the final energy is 1/2 m vf^2 set them equal.

    1/2 m vf^2=1/2 m vi^2 + mg265
    solve for Vf

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    bobpursley
  2. 200

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  3. I think it is infinity

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