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The reaction

CH3- N≡C → CH3- C≡N

is a first-order reaction. At 230.3°C, k = 6.29 x 10^-4 s^- 1. If [CH3 -N≡ is 1.00 x 10^-3 initially,
C]

[CH3-N ≡ C] is __________ after 1.000 x 10^3 s.

A) 5.33 x 10^-4

B) 1.00 x 10^-6

C) 4.27 x 10^-3

D) 2.34 x 10^-4

E) 1.88 x 10^-3

I asked this question before and tried to solve it on my own but im confused on how to set it up. i know the answer is A. but i just don't know how to get there.

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2 answers

  1. is this right?

    For first order kinetics:
    ln[A) = -kt + ln[Ao]
    ln[A) = - (6.29 x 10^-4 1/s)(1000. s) + ln (0.00100)
    ln[A) = -0.629 - 6.91 = -7.54
    [A) = e^-7.54 = 5.33 x 10^-4

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  2. Jes, I worked this problem for you yesterday. You don't go back and look at your posts? Here is how I did it (and Jack's looks ok, too).
    ln(No/N) = kt
    ln(1 x 10^-3/N) = 6.29 x 10^-4*1 x 10^3
    Solve for N. I get 5.33 x 10^-4

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