In a titration, 3.4 g of an acid (HX) requires 21.5 mL of 0.85 M NaOH(aq) for complete reaction. What is the molar mass of the acid? Answer in units of g/mol. im not really sure how to even start... but i calculated the moles of NaOH which i got to be .018 moles.... what do i do from here?
HX + NaOH ==> NaX + H2O
moles NaOH = M x L = ??
moles HX must be the same since the reaction is 1:1.
moles HX = grams/molar mass.
You know moles HC and grams HX, solve for molar mass HX.
I got 186.04 g/mole... did i do that right?
never mind, thank you :)
To find the molar mass of the acid (HX), you can use the stoichiometry of the balanced equation between the acid (HX) and the base (NaOH). Here are the steps to guide you:
Step 1: Determine the balanced equation between the acid (HX) and NaOH. Let's assume the balanced equation is: HX + NaOH → NaX + H2O.
Step 2: Calculate the number of moles of NaOH using the given volume and concentration. You have already calculated this as 0.018 moles.
Step 3: Use the balanced equation to relate the moles of NaOH to the moles of HX. From the balanced equation, the mole ratio between NaOH and HX is 1:1. Therefore, the moles of HX is also 0.018 moles.
Step 4: Use the given mass (3.4 g) and the calculated moles of HX (0.018 moles) to find the molar mass of HX. Molar mass (g/mol) = Mass (g) / Moles.
Molar mass of HX = 3.4 g / 0.018 moles = 188.89 g/mol.
Therefore, the molar mass of the acid (HX) is 188.89 g/mol.