We can calculate the kinetic energy of any moving object with a very simple formula: kinetic energy = 1/2 mv^2 ,where m is the object's mass and v is its velocity or speed. Table Energy Comparisons shows that metabolizing a candy bar releases about 10^6 joules.
A- How fast must the candy bar travel to have the same 10^6 joules in the form of kinetic energy? (Assume the candy bar's mass is 0.2 kilogram.)
B- Is your answer faster or slower than you expected?
3200m/s. just got it right on homework
gggh
it depends
To calculate the velocity at which the candy bar must travel to have 10^6 joules of kinetic energy, we can use the formula for kinetic energy: KE = 1/2 mv^2.
Given:
Mass (m) = 0.2 kg
Kinetic Energy (KE) = 10^6 J
We need to rearrange the formula to solve for velocity (v). Multiplying both sides of the equation by 2 and dividing by the mass, we get:
2KE = mv^2
v^2 = 2KE/m
v = √(2KE/m)
Now, substitute the given values into the formula:
v = √(2 * 10^6 J / 0.2 kg)
v = √(10^7 J / 0.2 kg)
v = √(5 * 10^6 J/kg)
v ≈ 2236.07 m/s
So, the candy bar must travel at approximately 2236.07 m/s to have 10^6 joules of kinetic energy.
To answer part B, we need to compare our answer to our expectations. This will depend on personal expectations or prior knowledge. However, generally speaking, speeds in the range of several thousands of meters per second are quite fast. Therefore, it is likely that the answer is faster than what one might expect for a candy bar.