The first step in the Ostwald process for making nitric acid is the formation of NO as follows; 4HN3 + 5O2 makes 4NO + 6 H2O. According to the equation, 5 moles of NH3 will react stoichiometrically with blank moles of O2 to form blank moles of NO. I can't figure out how to fill the blanks!
Ah, the joy of balancing equations! Let's solve this hilarious chemical puzzle together.
According to the equation, 4 moles of NH3 will react stoichiometrically with 5 moles of O2 to form 4 moles of NO. So, the blanks can be filled in as follows:
5 moles of NH3 will react stoichiometrically with 6.25 moles of O2 to form 5 moles of NO.
Great job for giving it a shot! Keep up the chemical comedy!
To determine the number of moles of O2 required to react with 5 moles of NH3 to form NO, we can use the stoichiometric coefficients in the balanced chemical equation.
According to the equation, the molar ratio between NH3 and O2 is 4:5.
This means that for every 4 moles of NH3, we need 5 moles of O2.
Since we have 5 moles of NH3, we can set up a proportion:
4 moles NH3 / 5 moles O2 = 5 moles NH3 / x moles O2
Cross-multiplying the equation, we get:
4 moles NH3 * x moles O2 = 5 moles NH3 * 5 moles O2
Simplifying the equation yields:
4x = 25
Dividing both sides by 4, we find:
x = 25/4
Therefore, 25/4 or 6.25 moles of O2 are required to react stoichiometrically with 5 moles of NH3 to form NO.
To determine the number of moles of O2 required and the number of moles of NO formed, we can use the stoichiometric coefficients in the balanced equation.
According to the balanced equation: 4NH3 + 5O2 → 4NO + 6H2O
The coefficients tell us that it takes 5 moles of O2 to react stoichiometrically with 4 moles of NH3, resulting in the formation of 4 moles of NO.
Therefore, you can fill the blanks as follows:
- 5 moles of NH3 will react stoichiometrically with 5 moles of O2 to form 4 moles of NO.
do it as a proportion:
5/4 =xmolesO2/5= ymolesNO/4