vinegar is 5.0% acetic acid, CH3COOH, by mass. vinegar has a density of 1.02 g/ml what is the madd of acetic acid in 50.0 ml of vinegar?
5.00% acetic acid by mass means 5.00 g acetic acid/100 g solution.
The 100 g soln can be converted to mL by using the density.
mass = volume x density and
v= m/d = 100/1.02 = 98.04 mL.
5 g x (50 mL/98.04 mL) = g acetic acid in 50 mL.
2.55
Ah, the age-old question of vinegar and its mysterious acetic acid content. Assuming that vinegar is indeed 5.0% acetic acid, let's embark on this acidic adventure.
First, we need to find out the mass of vinegar in 50.0 ml. Since vinegar has a density of 1.02 g/ml, we can multiply the volume (50.0 ml) by the density (1.02 g/ml):
50.0 ml x 1.02 g/ml = 51.0 g
Now that we know the mass of 50.0 ml of vinegar is 51.0 g, it's time to determine the mass of acetic acid. Since vinegar is 5.0% acetic acid, we can multiply the mass of vinegar (51.0 g) by the percentage of acetic acid (5.0% or 0.050):
51.0 g x 0.050 = 2.55 g
Voila! The mass of acetic acid in 50.0 ml of vinegar is approximately 2.55 grams. Please note that this calculation assumes the acetic acid and vinegar are well-mixed and that no clowns tried to juggle them along the way.
To find the mass of acetic acid in 50.0 ml of vinegar, we'll need to follow these steps:
Step 1: Calculate the volume of the acetic acid in the given volume of vinegar.
Since vinegar has a density of 1.02 g/ml, we can say that 1 ml of vinegar has a mass of 1.02 grams.
Therefore, 50.0 ml of vinegar will have a mass of (50.0 ml) x (1.02 g/ml) = 51.0 grams.
Step 2: Calculate the mass of acetic acid in 50.0 ml of vinegar.
Vinegar is 5.0% acetic acid by mass, which means that for every 100 grams of vinegar, 5 grams of it is acetic acid.
Therefore, in 51.0 grams of vinegar, the mass of acetic acid can be calculated as:
(5.0 / 100) x 51.0 grams = 2.55 grams.
So, the mass of acetic acid in 50.0 ml of vinegar is 2.55 grams.